Correct Answer - D
We find that P(E1)=
6
36
,P(E2)=
6
36
=
1
6
,
P(E3)=
1
2
,P(E1∩E2)=
1
36
,P(E2∩E3)=
3
36
=
1
12
,
P(E1∩E3)=
3
36
=
1
12
and P(E1∩E2∩E3)=0
Clearly, P(E1∩E2)=P(E1)P(E2)⇒E1,E2 are independent
P(E1∩E3)=P(E1)P(E3)⇒E1,E3 are independent
But, P(E1∩E2∩E3)≠P(E1)P(E2)P(E3)
⇒E1,E2,E3 are not independent
Thus, option (d) is incorrect.