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A fair die is thrown 20 times. The probability that on the 10th throw, the fourth six appears is `^20 C_(10)xx5^6//6^(20)` b. `120xx5^7//6^(10)` c. `8

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A fair die is thrown 20 times. The probability that on the 10th throw, the fourth six appears is ^20C10×56/620 b. 120×57/610 c. 84×56/610 d. none of these A. .20C10×55 620 B. 120×57 610 C. 84×56 610 D. none of these Select the correct answer from above options

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Correct Answer - C In the first 9 throws we should have three sixes and six non-sixes, and a six in the 10th throw, and thereafter whatever face appears no matter. ∴ Required Probability =.9C3( 1 6 )3×( 5 6 )6× 1 6 ×1×1×1....×110-×= 84×56 610 .

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