Correct Answer - A
Proceeding as in Example 14, we have
Favourable number of elementary events
= Coeff.of xk-3 in (1-x6)3(1-x)-3
Coeff.of xk-3 in (1-.3C1x6+..)(1-x)-3[∵9≤k≤14∴6≤k-3≤11]
=Coeff.of xk-3 in (1-x)-3-.3C1{Coeff.of xk-9 in (1-x)-3}
=.k-3+3-1C3-1-.3C1×.k-9+3-1C3-1
.k-1C2-3×.k-7C2
=
(k-1)(k-2)
2
-
3(k-7)(k-8)
2
=21k-k2-83
Hence, probability of required event =
21k-k2-83
63