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Six dice are thrown simultaneously. The probability that all of them show the different faces, is A. 1 6 5 1 B. 6 ! 6 6 6 C. 1 6 ! 1 D. 5 ! 6 ! 5 Select the correct answer from above options

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Correct Answer - B The total number of ways in which all dice show different faces is same as the number of arrangements of 6 numbers 1,2,3,4,5,6 by taking all at a time. So, favourable number of elementary events -6 ! Hence, required probaility = 6 ! 6 6 =

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