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A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then P(A∪B) is (1) 3 5 (2) 0 (3) 1 (4) 2 5 A. 1 B. 2/5 C. 3/5 D. 0 Select the correct answer from above options

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Correct Answer - A We have, P ( A ) = 3 6 = 1 2 , P ( B ) = 4 6 = 2 3 P and, P ( A ∩ B ) P = Probability of getting a number 3 and less than 5 = Probability of getting 4 = 1 6 4 ∴ P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ) = 1 2 + 2 3 − 1 6 = 1 ∴

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