Correct Answer -
5
10
5
n
(
S
)
=
(
6
×
6
)
=
36
n
.
Let E = event of getting the same number on two dice
or
E
=
{
(
1
,
1
)
,
(
2
,
2
)
,
(
3
,
3
)
,
(
4
,
4
)
,
(
5
,
5
)
,
(
6
,
6
)
}
E
.
∴
P
(
E
)
=
n
(
E
)
n
(
S
)
=
6
36
=
1
6
∴
⇒
⇒
P (not getting the same number on the two dice)
=
(
1
−
1
6
)
=
5
6
.
=
