Correct Answer -
5
9
5
Clearly,
n
(
S
)
=
(
6
×
6
)
=
36
n
.
Let
E
1
E
= event of getting an even number on the first die,
and
E
2
=
E
event of getting a total of 8 on both dice. Then,
E
1
=
{
(
2
,
1
)
,
(
2
,
2
)
,
.
.
,
(
2
,
6
)
,
(
4
,
1
)
,
(
4
,
2
)
,
.
.
,
(
4
,
6
)
,
(
6
,
1
)
,
(
6
,
2
)
,
.
.
,
(
6
,
6
)
}
,
E
E
2
=
{
(
2
,
6
)
,
(
3
,
5
)
,
(
4
,
4
)
,
(
6
,
2
)
}
.
E
∴
(
E
1
∩
E
2
)
=
{
(
2
,
6
)
,
(
3
,
5
)
,
(
4
,
4
)
,
(
5
,
3
)
,
(
6
,
2
)
}
.
∴
∴
n
(
E
1
)
=
18
,
n
(
E
2
)
=
5
and
n
(
E
1
∩
E
2
)
=
3
.
∴
Now, use
P
(
E
1
∪
E
2
)
=
P
(
E
1
)
+
P
E
2
−
P
(
E
1
∩
E
2
)
.
P
