We know that when two dice are thrown the same time, then the number of all possible outcomes is 36.
Let E be the event that the sum of the numbers appearing on the top of the two dice is more than 9.
The favourable outcomes are
(4,6),(5,5),(5,6),(6,4),(6,5),(6,6).
Number of favourable outcomes = 6.
∴ P(getting a sum more than 9) = P(E)=
6
36
=
1
6
.