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An antifreeze solution is prepared from `222.6 g` of ethylene glycol `[C_(2)H_(4)(OH)_(2)]` and `200 g` of water. Calculate the molality of the soluti

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An antifreeze solution is prepared from 222.6g of ethylene glycol [C2H4(OH)2] and 200g of water. Calculate the molality of the solution. If the density of the solution is 1.072gmL-1 then what shall be the molarity of the solution? Select the correct answer from above options

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Correct Answer - am=17.95,b.M=9.1 Mw of ethylene glycol =62g a. m= W2×1000 Mw2×W1 = 222.6×1000 62×200 =17.95molKg-1 b. Weight of solution =222.6+200=422.6g dsol=1.072gmL-1 Volume of solution = 422.6 1.072 =394.21mL M= W2×1000 Mw2×Vsol = 222.6×1000 62×394.21 =9.1M

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