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The vapour pressure of water is 12.3kPa at 300K . Calculate vapour pressure of 1 molal solution of a solute in it. Select the correct answer from above options

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Correct Answer - Ps=12.08kPa p∘=12.3kPa,pS=? M=1(1mole of solute is dissolved in 1L of solution ) Molarity of water = 1000 18 =55.56 ( or number of moles of water =55.56) p∘-pS p∘ =CHMi2= n2 n1+n2 = n2 n1 ( for dilute solution ) 12.3-pS 12.3 = 1 55.56 12.30pS= 12.3 55.56 =0.2213 pS=12.3-0.2213=12.078≈12.08kPa

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