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A `5%` solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The fre

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A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K. Select the correct answer from above options

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Correct Answer - 269.07K W2=5g,Wsolution=100g,Mw2=342g (C12H22O11) First case W1=100-5=95g ΔTf=273.15-271=2.15K ΔTf=Kf× W2×1000 Mw2×W1 2.15=Kf× 5×1000 342×95 Solve forKf⇒Kf=13.97 Second case W2=5g,W1=95g, ltbr. Mw2 of glucose (C6H12O6)=180g ΔTg=13.97× 5×1000 180×95 =4.085 273.15-T2=4.085 T2=273.15-4.085=269.07K

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