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The radioactive isotope . 60 27 C o . which has now replaced radium in the treatment of cancer can be made by a ( n , p ) a or ( n , γ ) ( reaction. For each reaction, indicate the appropriate target nucleus. If the half life of . 60 27 C o . is 7 year evaluate the decay constant in s − 1 s . Select the correct answer from above options

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Correct Answer - 3.142 × 10 − 9 s − 1 3.142 a . a i . . ( n . p ) i . 27 C o 60 i i . ... . ( n , γ ) . . 27 C o 60 + . . 1 H 1 . i . i . 28 N i 60 + . . 0 n 1 → ( T a r g e t n u c l e u s i s . 28 N i 60 ) . . 27 C o 60 + . 1 H 1 ) . i i . i . 27 C o 59 + . . 0 n 1 → ( T a r g e t n u c l e u s i s . 27 C o 59 ) . . 27 C o 60 + . . 1 H 1 ) . b . b t 1 / 2 t of . 27 C o 60 = 7 . years K = 0.693 t 1 / 2 K = 0.693 ( 7 y e a r s ) × ( 365 d a y y e a r − 1 ) ( 24 h r d a y − 1 ) ( 60 m i n h r − 1 ) ( 60 m i n s − 1 ) = = 0.693 7 × 3.15 × 10 7 s = = 31.42 × 10 − 10 s − 1 = = 3.142 × 10 − 9 s − 1 =

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