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The decomposition of dimethyl ether leads to the formation of CH4,H2, and CO and the reaction rate is given by Rate =k[CH3OCH3]3/2 The rate of reaction is followed by increase in the pressure in a closed vessel , so the rate can also be expressed in terms of the partial pressure of dimethyl either, i.e., Rate =k[pCH3OCH3]3/2 If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant ? Select the correct answer from above options

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Correct Answer - Unit of rate = bar min-1 Unit of k=bar1/2min-1 CH3OCH3→CH4+CO+H2 Rate =k[CH3OCH3]3/2 Units of rate = ΔP Δt = bar min-1 Units of k=[Conc]1-ntime-1 =[bar]1-3/2min-1 =bar-1/2min-1

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