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One hundred identical coins, each with probability `p ,` of showing up heads are tossed once. If `0 A. `(1)/(2)` B. `(49)/(101)` C. `(50)/(101)` D. `(51)/(101)` Select the correct answer from above options

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Correct Answer - D Let X denotes the number of coins showing heads up. Then, X is a binomial variate with n=100 and probabilituy of success p. We have P(X=51)=P(X=50) ⇒.100C51p51q49=.100C50p50q50, where q=1-p ⇒pq=.100C50.100C51=5150⇒p1-p=5150⇒p=51101

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