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There is a box containing 30 bulbs of which 5 are defective. If two bulbs are chosen at random from the box in succession without replacing the first,

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There is a box containing 30 bulbs of which 5 are defective. If two bulbs are chosen at random from the box in succession without replacing the first, what is the probability that both the bulbs chosen are defective? Select the correct answer from above options

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It is given that a box containing 30 bulbs of which 5 are defective with each trial independent of other trial Consider success bulb chosen is defective = 5/30 So the probability of success in the first trial P1 (success) = 5/30 So the probability of success in the second trial without replacement of the first draw P2 (success) = 4/29 Probability that both the bulbs chosen are defective, with each trial being independent

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