Question

A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is A. 3/28 B. 2/21 C. 1/28 D. 167/168 Select the correct answer from above options

Answer 1

There are total 8 balls in box. P(G) = 3/8 , Probability of green ball P(B) = 2/8 , Probability of blue ball Now, The probability of drawing 2 green balls and one blue ball is P(E)=P(G).P(G).P(B)+P(B).P(G).P(G)+P(G).P(B).P(G)