Correct Answer - D
The set A has n elements. So, it has
2
n
2
subsets.
Therefore, set P can be chosen in
2
n
C
1
2
ways. Similarly, set Q can also be chosen in
2
n
C
1
2
ways.
∴
∴
Sets P and Q can be chosen in
.
2
n
C
1
×
.
2
n
C
1
=
2
n
×
2
n
=
4
n
.
ways.
Suppose P contains r elements, where r varies from 0 to n.
Then, P can be chosen in
.
n
C
r
.
ways.
For Q to be disjoint from A, it should be chosen from the set of all subsets of set consisting of remaining n-r elements. This can be done in
2
n
−
r
2
ways. Therefore, P and Q can be chosen in
.
n
C
r
×
2
n
−
r
.
ways.
But, r can vary from 0 to n. Therefore, the total number of ways of selecting P and Q such that they are disjoint is
n
∑
r
=
0
.
n
C
r
2
n
−
r
=
(
1
+
2
)
n
=
3
n
∑
Hence, required probability
=
3
n
4
n
=
(
3
4
)
n
=