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A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls. A ball is drawn at random from the bag. Find the probability that it is (i) black, (ii) not green ,(iii) red or white, (iv) neither red nor green. Select the correct answer from above options

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Correct Answer - ` (i) 2/15 (ii) 11/15 (iii) 3/5 (iv) 2/5` Total number of balls = 4+5+2+4 = 15. (i) Number of black balls = 2. P(getting a black ball) = `2/15`. (ii) Number of balls which are not green = ` 4+5+2= 11`. P(getting a ball which is not green) ` 11/15`. (iii) Number of balls which are red or white = 5 +4 = 9 . P(getting a ball which is red or white ) = ` 9/15 = 3/5`. (iv) Number of balls which are neither red nor green = 4+2 = 6. P(getting a ball which is neither red nor green ) = ` 6/15 = 2/5`.

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