∴Number of red balls =8
and number of white balls 5
(i) P(all the three balls are white) =
.5C3
.13C3
=
5!
3!2!
13!
3!10!
=
5!
3!2!
×
3!10!
13!
=
5×4×3×2!
2!
×
10!
13×12×11×10!
=
5×4×3
13×12×11
=
5
13×11
=
5
143
5×4×3
13×12×11
=
5
13×11
=
5
143
(ii) P(all the three balls are red) =
.8C3
.13C3
=
8!
315!
13!
3!10!
=
8!
3!×5!
×
3!10!
13!
=
8×7×6×5!
5!
×
10!
13×12×11×10!
=
8×7×6
13×12×11
=
28
143
(iii) P(one ball is red and two balls are white)=
.8C1
.13C3
=
8×10
13×6×11
=
40
143