Question

A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls. A ball is drawn at random from the bag. Find the probability that it is (i) black (ii) not green, (iii) red or white, (iv) neither red nor green. Select the correct answer from above options

Answer 1

Probability = (number of favorable outcomes)/(Total number of outcomes) A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls. Total numbers of balls = 4 + 5 + 2 + 4 = 15 (i) Total numbers of black balls = Numbers of favorable outcomes= 2 P(getting a black ball) = 2/15 (ii) Total numbers of green balls = 4 Numbers of non-green balls = 15 – 4 = 11 P(not green ball) = 11/15 (iii) Total numbers of red and white balls = 5 + 4 = 9 P(red ball or white ball) = 9/15 = 3/5 (iv) Total numbers of red and green balls = 5 + 4 = 9 Number of balls which are neither red nor green = 15 – 9 = 6 P (getting neither red nor green ball) = 6/15 = 2/5