Correct Answer - 24∘C
k1=4.5×103s-1,k2=1.5×104s-1
T1=10+273=283K,T2=?
Ea=60kJmol-1
Using Arrhenius equation :
log(k2)
k1
=
Ea
2.303R
(
T2-T1
T1T2
)
log
1.5×104
4.5×103
=
60×1000Jmol-1
2.303×8.314JK-1mol-1
(
T2=283
283T2
)
orlog3.333=3133.63(
T2-283
283T2
)
or
0.5228
3133.63
=(
T2-283
293T2
)
or0.0472T2=T2-283
or0.9528T2=283
orT2=
283
0.9528
=297K=297-273∘C=24∘C