Let E be the event of having at least one boy
The probability that each child will be a girl= 1/2
The probability that each child will be a boy = 1/2
The probability of no boys = All are girls = 1/2 x 1/2 x 1/2 = 1/8
Then, the number of favorable outcome is P(E) –P(not E) = 1 where
Let E be the event of having at least one boy, then P(E) is probability of having atleast one boy and
P(not E) = Probability of having no boys.
Therefore,
Probability (at least 1 boy) = 1 – Probability (no boys)= 1 – 1/8 = 7/8
