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In a family of 3 children, find the probability of having at least one boy. Select the correct answer from above options

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Correct Answer - ` 7/8` All possible outcomes are BBB, BBG,BGB, GBB,BGG,GBG, GGB, GGG. Number of all possible outcomes = 8. Let E be the event of having at least one boy. Then, E contains GGB, GBG, BGG,BBG,BGB,GBB,BBB. Number of cases favourable to E = 7. ` :. ` required probability ` P(E ) = 7/8`.

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