Question

In a single throw of two coins, find the probability of getting (i) both tails, (ii) at least 1 tail, (iii) at the most 1 tail. Select the correct answer from above options

Answer 1

We know that the coin has two sides head (H) and tail (T) So the possible outcomes are Xm. (where x is the number of outcomes when a coin is tossed and m is number of coins) (i) When there are 2 coins∴ 22= 4 i.e. head and tail ∴ The possible outcomes are HH, HT, TH, TT. Total possible outcomes =4 ∴ Chances of getting a 2 tails = 1, i.e. TT By using the formula, Probability p () = number of favorable outcomes/ total number of outcomes ∴ Probability of getting a tail p (bothT) = number of two tails occurred/total number of outcomes = ¼ (ii) When there are 2 coins∴ 22= 4 i.e. head and tail ∴ The possible outcomes are HH, HT, TH, TT. Total possible outcomes =4 ∴ Chances of getting atleast 1 tail = 3, i.e. HT, TH, TT By using the formula, Probability p () = number of favorable outcomes/ total number of outcomes ∴ Probability of getting a tail p (atleast 1T) = number of times 1 tail occurred/total number of outcomes =3/4 (iii) When there are 2 coins∴ 22= 4 i.e. head and tail ∴ The possible outcomes are HH, HT, TH, TT. Total possible outcomes =4 ∴ Chances of getting atmost 1 tail = 3, i.e. HT, TH, TT By using the formula, Probability p () = number of favorable outcomes/ total number of outcomes ∴ Probability of getting a tail p (atmost 1T) = number of times 1 tail occurred/total number of outcomes =3/4