Given: Three coins are tossed together.
By using the formula,
P (E) = favourable outcomes / total possible outcomes
Total number of possible outcomes is 23 = 8
(i) Let E be the event of getting exactly two heads
E = {(H, H, T) (H, T, H) (T, H, H)}
n (E) = 3
P (E) = n (E) / n (S)
= 3 / 8
(ii) Let E be the event of getting at least two heads
E= {(H, H, T) (H, T, H) (T, H, H) (H, H, H)}
n (E)=4
P (E) = n (E) / n (S)
= 4 / 8
= 1/2
(iii) Let E be the event of getting at least one head and one tail
E = {(H, T, T) (T, H, T) (T, T, H) (H, H, T) (H, T, H) (T, H, H)}
n (E) = 6
P (E) = n (E) / n (S)
= 6 / 8
= 3/4
