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A die is thrown. Find the probability of (i) getting a 5 (ii) getting a 2 or a 3 (iii) getting an odd number (iv) getting a prime number (v) getting a multiple of 3 (vi) getting a number between 3 and 6 Select the correct answer from above options

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We know, Probability of occurrence of an event = (Total number of favorable outcomes) / (Total number of outcomes) Total outcomes are 1, 2, 3, 4, 5, 6. Total number of outcomes = 6 (i) getting a 5 Total number of desired outcomes i.e. getting 5 = 1 Probability (getting a 5) = 1/6 (ii) getting a 2 or a 3 Total number of desired outcomes i.e. getting 2 or 3 = 2 Probability (getting 2 or 3) = 2/6 = 1/3 (iii) getting an odd number Total number of desired outcomes i.e. an odd number = 1, 3, 5 = 3 Probability (getting an odd number) = 3/6 = 1/2 (iv) getting a prime number Total number of desired outcomes i.e. prime number = 2, 3, 5 = 3 Probability (getting a prime number) = 3/6 = 1/2 (v) getting a multiple of 3 Multiple of 3 = 3, 6 Total number of desired outcomes = 2 Probability (getting a multiple of 3) = 2/6 = 1/3 (vi) getting a number between 3 and 6 Number between 3 and 6 = 4, 5 Total number of desired outcomes = 2 Probability (getting a number between 3 and 6) = 2/6 = 1/3

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