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A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just by guessing is (1) 13 35 (2) 11 35 (3) 10 35 (4) 17 35 A. 17 35 B. 13 35 C. 11 35 D. 1 35 Select the correct answer from above options

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Correct Answer - C It is a problem on binomial distribution in which n=5,p= probability that the answer of a question is correct = 1 3 andq=1- 1 3 = 2 3 . Let X denote the number of correct answer. Then, P(X=r)=.5Cr( 1 3 )r( 2 3 )5-r,r=0,1,2,....,5 Required Probability =P(X≥4)=P(X=4)+P(X=5) =.5C4( 1 3 )4( 2 3 )1+.5C5( 1 3 )5( 2 3 )0= 10 35 + 1 35 = 11 35

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