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If six students, including two particular students A and B, stand in a row, then the probability that A and B are separated with one student in between them is A. 8/15 B. 1/5 C. 2/15 D. 4/15 Select the correct answer from above options

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Correct Answer - D Total number of ways in which 6 students can stand in row is 6!. One student can stand between A and B in .4C1×2! ways. Considering these three as one individual we have 4 students who can stand in a row in 4! Ways. Therefore, number of ways in which one student is there between A and B and is .4C1×2!×4! . Hence, required probability = .4C1×2!×4! 6! = 4 5

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