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If A and B are arbitrary events, then a) `P(A nn B) ge P(A)+ P(B)` (b) `P(A uu B) le P(A)+ P(B)` (c) `P(AnnB)=P(A)+ P(B)` (d)None of these

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If A and B are arbitrary events, then a) P(A∩B)≥P(A)+P(B) (b) P(A∪B)≤P(A)+P(B) (c) P(A∩B)=P(A)+P(B) (d)None of these A. P(A∩B)≥P(A)+P(B) B. P(A∪B)≤P(A)+P(B) C. P(A∩B)=P(A)+P(B) D. none of these Select the correct answer from above options

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Correct Answer - B We have, P(A∪B)=P(A)+P(B)-P(A∩B) ⇒P(A∪B)≤P(A)+P(B)

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