Correct Answer - C
Let A be the event of drawing a diamond card in the first draw and B be the event of drawing a diamond card in the second draw. Then,
P
(
A
)
=
.
13
C
1
.
52
C
1
=
13
52
=
1
4
P
After drawing a diamond card in first draw 51 cards are left out of which 12 cards are diamond cards.
∴
P
(
B
/
A
)
∴
=Probability of drawing a diamond card in second draw when a diamond card has already been drawn in first draw
P
(
B
/
A
)
=
.
12
C
1
.
51
C
1
=
12
51
=
4
17
P
Hence,
Required probability
=
P
(
A
∩
B
)
=
⇒
⇒
Required probability
=
P
(
A
)
P
(
B
/
A
)
=
⇒
⇒
Required probability
=
1
4
×
4
17
=
1
17
=
