Let S be the sample space. Then,
n(S) = number of ways of selecting 2 cards out of 52
=52C2=
(52×51)
(2×1)
=1326.
Let E = event that both the cards drawn are aces. Then,
n(E) = number of ways of drawing 2 aces out of 4
=4C2=
(4×3)
(2×1)
=6.
P(getting 2 aces) =P(E)=
n(E)
n(S)
=
6
1326
=
1
221
.