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Find the probability that the birth days of six different persons will fall in exactly two calendar months. Select the correct answer from above options

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Total cases=12⋅12⋅12⋅12⋅12⋅12=126 Favorable Cases=.12C2[.6C1⋅.22C1+.6C2⋅.2C1+.6C3⋅.2C1] P= .12C2[.6C1⋅.2C1+.6C2⋅.2C1+.6C3⋅.2C1] 126 .

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