Let S denote the sample space. Then, n(S) = 52.
(i) Let E1=
event of drawing an ace.
Since, the number of all aces is 4, so n(E1)=4.
∴
P(getting an ace) =P(E1)=
n(E1)
n(S)
=
4
52
=
1
13
.
(ii) Let E2=
event of getting a heart. Then, n(E2)=13.
∴
P(getting an heart) P(E2)=
n(E2)
n(S)
=
13
52
=
1
4
.
(iii) Let E3=
event of getting an eight of hearts. Then, n(E3)=1
.
∴
P(getting an eight of hearts) =P(E3)=
n(E3)
n(S)
=
1
52
.
(iv) Let E4=
event of getting a club. Then, n(E4)=13
.
∴
P(getting a club) =P(E4)=
n(E4)
n(S)
=
13
52
=
1
4
.
(v) Let E5=
event of getting a red card. Then, n(E5)=26
.
∴
P(getting a red card) =P(E5)=
n(E5)
n(S)
=
26
52
=
1
2
.
(vi) Let E6=
event of getting a face card. Then, n(E6)=16
.
∴
P(getting a red card) =P(E6)=
n(E6)
n(S)
=
16
52
=
4
13
.
(vii) Let E7=
event of getting a diamond. Then, n(E7)=13
.
∴
P(getting a diamond) =P(E7)=
n(E7)
n(S)
=
13
52
=
1
4
.
(viii) Let E8=
event of getting a jack. Then, n(E8)=4
.
∴
P(getting a jack) =P(E8)=
n(E8)
n(S)
=
4
52
=
1
13
.
(ix) Let E9=
event of getting a black card. Then, n(E9)=26
.
∴
P(getting a black card) =P(E9)=
n(E9)
n(S)
=
26
52
=
1
2
.