Correct Answer -
11
36
11
Clearly,
n
(
S
)
=
(
6
×
6
)
=
36
n
.
Let
E
1
E
= event that the first throw shows a 4,
and
E
2
=
E
event that the second throw shows a 4.
Then,
(
E
1
∩
E
2
)
=
(
event that each throw shows a 4.
∴
E
1
=
{
(
4
,
1
)
,
(
4
,
2
)
,
(
4
,
3
)
,
(
4
,
4
)
,
(
4
,
5
)
,
(
4
,
6
)
}
,
∴
and
E
2
=
{
(
1
,
4
)
,
(
2
,
4
)
,
(
3
,
4
)
,
(
4
,
4
)
,
(
5
,
4
)
,
(
6
,
4
)
}
E
,
∴
(
E
1
∩
E
2
)
=
{
(
4
,
4
)
}
.
∴
Now, use
P
(
E
1
∪
E
2
)
=
P
(
E
1
)
+
P
(
E
2
)
−
P
(
E
1
∩
E
2
)
.
P
