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Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her,

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Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is (A) `1/2` (B) `1/3` (C) `2/3` (D) `3/4` A. `1//2` B. `1//3` C. `2//3` D. `3//4` Select the correct answer from above options

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Correct Answer - A Total number of ways to arrange 3 boys and 2 girls are 5!. According to given condition, following cases may mise. `{:(B" "G" "G" "B" "B),(G" "G" "B" "B" "B),(G" "B" "G" "B" "B),(G" "B" "B" "G" "B),(B" "G" "B" "G" "B):}` So number of favorite ways `=5xx3!xx2!=60` `therefore " Required probility " =(60)/120)=1/2`

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