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Six boys and six girls sit in a row randomly. Find the probability that (i) the six girls sit together, (ii) the boys and girls sit alternately. Select the correct answer from above options

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The total number of arrangementa of six boys and six girls = 12 ! `therefore` Required probability `=(6!xx7!)/((12!))=1/132` [since, we consider six girls at one person] (ii) Required probability `=(2xx 6! Xx 6! )/(12!)=1/462 `

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