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Find the value of ‘y’ in the equation –(-1/j6)Va+(1/5+1/j5-1/j6)Vb=y obtained from the following circuit. (a) (10∠30^o)/5 (b) -(10∠30^o)/5 (c) (5∠30^o)/5 (d) (-5∠30^o)/5 The question was asked during an internship interview. The above asked question is from Nodal Analysis in portion Steady State AC Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right choice is (b) -(10∠30^o)/5 The explanation is: We got Ybb=1/5+1/j5-1/j6 and Yab=–(-1/j6). The mutual admittance between node b and a is the sum of the admittances between nodes b and a. I2=-(10∠30^o)/5=y.

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