Question

Find the current through (2+j5) Ω impedance considering 20∠30⁰ voltage source. (a) 8.68∠-42.53⁰ (b) 8.68∠42.53⁰ (c) 7.68∠42.53⁰ (d) 7.68∠-42.53⁰ I got this question in a national level competition. The origin of the question is Superposition Theorem in portion Steady State AC Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Correct choice is (b) 8.68∠42.53⁰ The explanation is: The current through (2+j5) Ω impedance considering 20∠30⁰ voltage source is I2 = 20∠30^o×j4/(2+j9) = 8.68∠42.53^o A.