Question

Find the voltage across (2+j5) Ω impedance using Superposition theorem. (a) 40.85∠72.53⁰ (b) 40.85∠-72.53⁰ (c) 41.85∠72.53⁰ (d) 41.85∠-72.53⁰ The question was asked during an online exam. This intriguing question originated from Superposition Theorem in division Steady State AC Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct option is (a) 40.85∠72.53⁰ Explanation: The voltage across (2+j5) Ω impedance using Superposition theorem is the sum of the voltages V1 and V2. V = V1+V2 = 29.16∠-9.28^o+46.69∠110.72^o=40.85∠72.53^o V.