In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 10Ω and capacitance C = 1µF. The particular integral of the solution of ‘ip’ is?
(a) ip = (4.99×10^-3) cos(100t+π/4-89.94^o)
(b) ip = (4.99×10^-3) cos(100t-π/4-89.94^o)
(c) ip = (4.99×10^-3) cos(100t-π/4+89.94^o)
(d) ip = (4.99×10^-3) cos(100t+π/4+89.94^o)
I have been asked this question during an internship interview.
This intriguing question originated from Sinusoidal Response of an R-C Circuit in portion Transients of Network Theory
Select the correct answer from above options
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