Question

In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the particular solution. (a) ip = 0.6cos(500t + π/4 + 88.5⁰) (b) ip = 0.6cos(500t + π/4 + 89.5⁰) (c) ip = 0.7cos(500t + π/4 + 89.5⁰) (d) ip = 0.7cos(500t + π/4 + 88.5⁰) I got this question in unit test. Enquiry is from Sinusoidal Response of an R-L-C Circuit topic in section Transients of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct option is (d) ip = 0.7cos(500t + π/4 + 88.5⁰) Best explanation: Particular solution is ip = V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC-ωL)/R)). ip = 0.7cos(500t + π/4 + 88.5⁰).