Question

The circuit shown below is at steady state before the switch closes at t=0. The switch is closed for 1.5 s and is then opened. At t = 2 s, V (t) will be? (a) 5.12 V (b) 6.43 V (c) 8.57 V (d) 9.88 V The question was posed to me in a job interview. The above asked question is from Calculation of I(0+), di/dt(0+), d2I/dt2(0+) in Circuits Involving both Capacitor and Inductor in portion Application of the Laplace Transform in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right choice is (c) 8.57 V The best explanation: V (1.5s) = 5.002 V For t > 1.5 s, τ = 8 × 0.05 = 0.4 V (t) = 10+ (5-10)e^{\frac{-(t-1.5)}{0.4}} = 10 – 5e^-2.5(t-1.5) For t≥1.5 s, V (2 s) = 8.57 V.