Question

A parallel RLC circuit with R1 = 20, L1 = \frac{1}{100} and C1 = \frac{1}{200} is scaled giving R2 = 10^4, L2 = 10^-4 and C2, the value of C2 is ___________ (a) 0.10 nF (b) 0.3 nF (c) 0.2 nF (d) 0.4 nF This question was addressed to me in an interview for internship. My question comes from Series-Parallel Interconnection of Two Port Network in section Two-Port Networks of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct answer is (c) 0.2 nF For explanation I would say: K1 = \frac{R_2}{R_1} = \frac{10^4}{20} = 5 X 10^2 = 500 Ω And \frac{L_1}{L_2} = \frac{kω}{k_1} Or, \frac{kω}{k_1} = \frac{L_1}{L_2} X k_1 Or, \frac{10^{-2}}{10^{-4} X 5 X 10^2} = 5 X 10^4 Or, C2 = \frac{C_1}{kω.k_1} = \frac{0.5 X 10^{-2}}{5 X 10^4 X 500} = 0.02 X 10^-8 = 0.2 nF.