Question

In a series RLC circuit R = 10 kΩ, L = 0.5 H and C = \frac{1}{250} μF. Calculate the frequency when the circuit is in a state of resonance. (a) 4.089 × 10^4 Hz (b) \frac{11111.1}{π}Hz (c) 4.089π × 10^4 Hz (d) \frac{1}{π} × 10^4 Hz I got this question in a job interview. This interesting question is from Problems of Series Resonance Involving Frequency Response of Series Resonant Circuit topic in portion Resonance & Magnetically Coupled Circuit of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct choice is (b) \frac{11111.1}{π}Hz Easiest explanation: Resonance frequency = \frac{1}{2π\sqrt{LC}} = \frac{1}{2π\sqrt{\frac{1}{250} × 10^{-6} × 0.5}} = \frac{11111.1}{π}Hz.