Jmeter Regex to match for date of the format dd/mm/yyyy using "\d"

Question

I have a data which looks like EX:992215:SHOW:CMS016:000335:ESP:15:EUR:Euro:4:14:01/05/2009‌:30/04/2017:52:26: I wanted to read the last value i.e 26 using jmeter regular expression extractor. I tried with the following regex, .+:992215:.+:.+:\d+:.+:.+:.+:.+:\d+:\d+:\d+/\d+/\d+:\d+/\d+/\d+:\d:(.+?): The regex is not working from \d+/\d+/\d+:\d+/\d+/\d+:\d:(.+?): which is the date part. Can anyone please help me out with this. JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

If you do not care what is between :992215: and the number after the last : on the line, use :992215:.*:(\d+) See this regex demo Details: :992215: - a literal string .*: - any 0+ characters other than a newline up to the last : on the line (\d+) - Group $1$ capturing 1+ digits. If you want to use your own regex, what you might try is to replace all .+ (that is, the greedy dot pattern matching any 1+ characters other than a newline as many as possible) with [^:]+ (a negated character class matching 1+ chars other than : as many as possible).