Switching an array's elements in C

Question

So i want to switch the elements of an array with 32 integers "n" times. All elements should be on the next position and the last should be at the first. I tried something like this: while(scanf("%d", &n) != EOF) { for(int j=0; j<n; j++) for(int i=1; i<31; i++) { t[0]=t[31]; tmp=t[i]; t[i]=t[i+1]; } } Im not sure how could I use the tmp variable to solve this problem. this is the array's element: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 and it should look like this if the n=1: 32 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

Following is not an edit of your code, but a more efficient solution with the runtime of O(n): void rightshift(char array[LENGTH]) { int i, next = array[0]; for (i = 1; i < LENGTH; i++) { char temp = array[i]; array[i] = next; next = temp; } array[0] = next; }