Gremlin: Generate a list by location of counts for active versus inactive users

Question

I have vertices people, usertype, and location. People has outgoing edges people_location and people_usertype. People has property 'name', usertype has property 'activationStatus', and location has property 'name'. I want to create a list that looks like this: [[1]: https://i.stack.imgur.com/lKzZL.png] I want the count of people, by location, for activationStatus "active" and "inactive" where the location has "US" in it. This is all I have only for count of people by location where the location 'name' begins with US: g.V()hasLabel('people').out('people_publicisofficelocation') .filter(has('name',between('US','UT'))) .groupCount().by('name') It is running but not yielding results. JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

You can simulate 'starts with' behavior in versions of TinkerPop prior to 3.4 using something like has('name',between('US','UT')) so you could replace the filter line above with that. If the graph implementation you are using supports TinkerPop 3.4 there are additional text predicates you can use for begins with, ends with and contains. As others have said if you can post some sample addV() and addE() steps that build part of your graph it will be easier to give a more precise answer.