Find key, value pair in dict according to second value of tuples using itemgetter() method

Question

I have the following dictonary: inventory = {'apple':(3, 133), 'banana':(9, 407), 'pear':(17, 205), 'orange':(1, 91)} I would like to find key, value pair according to max value of the second element in the tuple so in this case it should return: banana':(9, 407) I know I can get this result using lambda: key_max = max(inventory.keys(), key=(lambda k: inventory[k][1])) print key_max, inventory[key_max] However I try to receive same result using itemgetter() method as I read it is faster but I can only get data according to the value of first element of the tuple: from operator import itemgetter print max(inventory.iteritems(), key = itemgetter(1)) Is there a way I could get same result using itemgetter() method? JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

Although I don't see the point of this exercise... Here's a solution using only itemgetter and no lambdas, as was the original question: key = max(zip(inventory.keys(), map(itemgetter(1), inventory.values())), key=itemgetter(1))[0] print(key, inventory[key]) # banana (9, 407) Note that the above will only be efficient in Python 3.x where the built-in functions return iterators / view objects instead of lists. An equally efficient Python 2.x equivalent requires the use of library functions such as itertools.izip: # from itertools import izip, imap key = max(izip(inventory.iterkeys(), imap(itemgetter(1), inventory.itervalues())), key=itemgetter(1))[0] print key, inventory[key]