How can I wrap BOOST in a separate namespace?

Question

I'm looking to have two versions of BOOST compiled into a project at the same time. Ideally they should be usable along these lines: boost_1_36_0::boost::shared_ptr someClass = new SomeClass(); boost_1_35_0::boost::regex expression("[0-9]", boost_1_35_0::boost::regex_constants::basic); JavaScript questions and answers, JavaScript questions pdf, JavaScript question bank, JavaScript questions and answers pdf, mcq on JavaScript pdf, JavaScript questions and solutions, JavaScript mcq Test , Interview JavaScript questions, JavaScript Questions for Interview, JavaScript MCQ (Multiple Choice Questions)

Answer 1

I read (well scanned) through the development list discussion. There's no easy solution. To sum up: Wrapping header files in a namespace declaration namespace boost_1_36_0 { #include } namespace boost_1_35_0 { #include } Requires modifying source files Doesn't allow for both versions to be included in the same translation unit, due to the fact that macros do not respect namespaces. Defining boost before including headers #define boost boost_1_36_0 #include #undef boost #define boost boost_1_35_0 #include #undef boost Source files can simply be compiled with -Dboost=boost_1_36_0 Still doesn't address macro conflicts in a single translation unit. Some internal header file inclusions may be messed up, since this sort of thing does happen. #if defined(SOME_CONDITION) # define HEADER #else # define HEADER #endif But it may be easy enough to work around those cases. Modifying the entire boost library to replace namespace boost {..} with namespace boost_1_36_0 {...} and then providing a namespace alias. Replace all BOOST_XYZ macros and their uses with BOOST_1_36_0_XYZ macros. This would likely work if you were willing to put into the effort.