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Two elements `A` and `B` form compounds having molecular formula `AB_(2)` and `AB_(4)`. When dissolved in `20 g` of benzene, `1 g`of `AB_(2)` lowers t

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Two elements A and B form compounds having molecular formula AB2 and AB4 . When dissolved in 20g of benzene, 1g of AB2 lowers the freezing point by 2.3K , whereas 1.0g of AB4 lowers it by 1.3K . The molar depression constant for benzene is 5.1Kkgmol-1 . Calculate the atomic mass of A and B . Select the correct answer from above options

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Correct Answer - AwA=25.58μ,AwB=42.64μ W2(AB2)=1g,Mw2(Ag2)=? First case W1(C6H6)=20g,Mw1(C6H6)=78.9g ΔTf=2.3K,Kf=5.1 2.3=5.1× 1×1000 Mw2(AB2)×20 ……..(i) Second case Mw2(AB2)=110.86gmol-1 W2(AB4)=1g,Mw2(AB4)=? W1(C6H6)=20g,ΔTf=1.3K 1.3=5.1× 1×1000 Mw2(AB4)×20 ......(ii) Mw2(AB4)=196.15gmol-1 Let the atomic weight of A=x Let the atomic weight of B=y x+2y=110.86 x+4y=196.15 Solve for x for y , we get y=42.64,x=25.58 ∴ Atomic weight of A=25.58μ Atomic weight B=42.64μ

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